SQL查询至少连续n天登录的用户

以连续3天为例，使用工具：MySQL。


1.创建SQL表：

create table if not exists orde(id varchar(10),date datetime,orders varchar(10));

insert into orde values(‘1’ , ‘2022/1/1’,10 );

insert into orde values(‘1’ , ‘2022/1/2’,109 );

insert into orde values(‘1’ , ‘2022/1/3’,150 );

insert into orde values(‘1’ , ‘2022/1/4’,99);

insert into orde values(‘1’ , ‘2022/1/5’,145);

insert into orde values(‘1’ , ‘2022/1/6’,1455);

insert into orde values(‘1’ , ‘2022/1/7’,199);

insert into orde values(‘1’ , ‘2022/1/8’,188 );

insert into orde values(‘4’ , ‘2022/1/1’,10 );

insert into orde values(‘2’ , ‘2022/1/2’,109 );

insert into orde values(‘3’ , ‘2022/1/3’,150 );

insert into orde values(‘4’ , ‘2022/1/4’,99);

insert into orde values(‘5’ , ‘2022/1/5’,145);

insert into orde values(‘6’ , ‘2022/1/6’,1455);

insert into orde values(‘7’ , ‘2022/1/7’,199);

insert into orde values(‘8’ , ‘2022/1/8’,188 );

insert into orde values(‘9’ , ‘2022/1/1’,10 );

insert into orde values(‘9’ , ‘2022/1/2’,109 );

insert into orde values(‘9’ , ‘2022/1/3’,150 );

insert into orde values(‘9’ , ‘2022/1/4’,99);

insert into orde values(‘9’ , ‘2022/1/6’,145);

insert into orde values(‘9’ , ‘2022/1/9’,1455);

insert into orde values(‘9’ , ‘2022/1/10’,199);

insert into orde values(‘9’ , ‘2022/1/13’,188 );查看数据表：

2.使用row_number() over()  排序函数计算每个id的排名，SQL如下：

select *,row_number() over(partition by id order by date ) ‘rank’

from orde

where orders is not NULL;查看数据表:

3.将date日期字段减去rank排名字段，SQL如下：

select *,DATE_SUB(a.date,interval a.rank day) ‘date_sub’

from(

select *,row_number() over(partition by id order by date ) ‘rank’

from orde

where orders is not NULL

) a;查看数据：

4.根据id和date分组并计算分组后的数量(count)、计算最早登录和最晚登录的时间，SQL如下：

select b.id,min(date) ‘start_time’,max(date) ‘end_time’,count(*) ‘date_count’

from(

select *,DATE_SUB(a.date,interval a.rank day) ‘date_sub’

from(

select *,row_number() over(partition by id order by date ) ‘rank’

from orde

where orders is not NULL

) a

) b

group by b.date_sub,id

having count(*) >= 3

; 查看数据：

参考资料：

SQL查询至少连续七天下单的用户

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